CalculusSuperchallengeDifferential Equations ShareDifferential Equations · Superchallenge problemSolve the initial value problem dydx=16x+3\dfrac{dy}{dx} = 16x + 3dxdy=16x+3 with y(0)=12y(0) = 12y(0)=12, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept