CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=14x−1\dfrac{dy}{dx} = 14x - 1dxdy=14x−1 with y(0)=5y(0) = 5y(0)=5, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept