CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=16x+1\dfrac{dy}{dx} = 16x + 1dxdy=16x+1 with y(0)=4y(0) = 4y(0)=4, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept