CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=16x−1\dfrac{dy}{dx} = 16x - 1dxdy=16x−1 with y(0)=−10y(0) = -10y(0)=−10, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept