CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=14x+8\dfrac{dy}{dx} = 14x + 8dxdy=14x+8 with y(0)=0y(0) = 0y(0)=0, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept