CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=16x+8\dfrac{dy}{dx} = 16x + 8dxdy=16x+8 with y(0)=−3y(0) = -3y(0)=−3, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept