CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=18x+2\dfrac{dy}{dx} = 18x + 2dxdy=18x+2 with y(0)=1y(0) = 1y(0)=1, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept