CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=14x+6\dfrac{dy}{dx} = 14x + 6dxdy=14x+6 with y(0)=−10y(0) = -10y(0)=−10, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept