CalculusHardDifferential Equations ShareDifferential Equations · Hard problemSolve the initial value problem dydx=2x+8\dfrac{dy}{dx} = 2x + 8dxdy=2x+8 with y(0)=−1y(0) = -1y(0)=−1, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept