CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=22x+6\dfrac{dy}{dx} = 22x + 6dxdy=22x+6 with y(0)=11y(0) = 11y(0)=11, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept