CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=14x+10\dfrac{dy}{dx} = 14x + 10dxdy=14x+10 with y(0)=−3y(0) = -3y(0)=−3, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept