CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=8x+6\dfrac{dy}{dx} = 8x + 6dxdy=8x+6 with y(0)=−1y(0) = -1y(0)=−1, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept