CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=22x+2\dfrac{dy}{dx} = 22x + 2dxdy=22x+2 with y(0)=−4y(0) = -4y(0)=−4, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept