CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=16x−2\dfrac{dy}{dx} = 16x - 2dxdy=16x−2 with y(0)=8y(0) = 8y(0)=8, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept