CalculusChallengeDifferential Equations ShareDifferential Equations · Challenge problemSolve the initial value problem dydx=16x−8\dfrac{dy}{dx} = 16x - 8dxdy=16x−8 with y(0)=−2y(0) = -2y(0)=−2, then find y(2)y(2)y(2).Check Show answer Walk through it step by step Practice more like this Review this concept