CalculusSuperchallengeThe Derivative ShareThe Derivative · Superchallenge problemLet g(x)=f(x)+4g(x) = f(x) + 4g(x)=f(x)+4 where f′(15)=19f'(15) = 19f′(15)=19. What is g′(15)g'(15)g′(15)?Check Show answer Walk through it step by step Practice more like this Review this concept