CalculusChallengeThe Derivative ShareThe Derivative · Challenge problemLet g(x)=f(x)+1g(x) = f(x) + 1g(x)=f(x)+1 where f′(14)=15f'(14) = 15f′(14)=15. What is g′(14)g'(14)g′(14)?Check Show answer Walk through it step by step Practice more like this Review this concept