CalculusChallengeThe Derivative ShareThe Derivative · Challenge problemLet g(x)=f(x)+1g(x) = f(x) + 1g(x)=f(x)+1 where f′(13)=14f'(13) = 14f′(13)=14. What is g′(13)g'(13)g′(13)?Check Show answer Walk through it step by step Practice more like this Review this concept