CalculusChallengeThe Derivative ShareThe Derivative · Challenge problemLet g(x)=f(x)+3g(x) = f(x) + 3g(x)=f(x)+3 where f′(14)=17f'(14) = 17f′(14)=17. What is g′(14)g'(14)g′(14)?Check Show answer Walk through it step by step Practice more like this Review this concept