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Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+1y′−6y=0y'' + 1y' - 6y = 0 with y(0)=−2y(0) = -2, y′(0)=6y'(0) = 6. The solution is y=c1e2t+c2e−3ty = c_1e^{2t} + c_2e^{-3t}. Find c1c_1.