MathCastle
Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+5y′+6y=0y'' + 5y' + 6y = 0 with y(0)=2y(0) = 2, y′(0)=−4y'(0) = -4. The solution is y=c1e−3t+c2e−2ty = c_1e^{-3t} + c_2e^{-2t}. Find c1c_1.