MathCastle
Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′−3y′+2y=0y'' - 3y' + 2y = 0 with y(0)=5y(0) = 5, y′(0)=6y'(0) = 6. The solution is y=c1e1t+c2e2ty = c_1e^{1t} + c_2e^{2t}. Find c1c_1.