MathCastle
Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+4y′+3y=0y'' + 4y' + 3y = 0 with y(0)=−3y(0) = -3, y′(0)=9y'(0) = 9. The solution is y=c1e−1t+c2e−3ty = c_1e^{-1t} + c_2e^{-3t}. Find c1c_1.