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Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+0y′−1y=0y'' + 0y' - 1y = 0 with y(0)=−2y(0) = -2, y′(0)=4y'(0) = 4. The solution is y=c1e−1t+c2e1ty = c_1e^{-1t} + c_2e^{1t}. Find c1c_1.