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Differential EquationsHardSecond-Order Linear Equations

Second-Order Linear Equations · Hard problem

Solve y′′+0y′−9y=0y'' + 0y' - 9y = 0 with y(0)=−3y(0) = -3 and y′(0)=−3y'(0) = -3. The solution has the form y=Ae3t+Be−3ty = Ae^{3t} + Be^{-3t}; find AA and BB.