Counting & ProbabilityEasyBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Easy problemEvaluate ∑k=04k(4k)\displaystyle\sum_{k=0}^{4}k\binom{4}{k}k=0∑4k(k4).Check Show answer Walk through it step by step Practice more like this Review this concept