Counting & ProbabilityEasyBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Easy problemEvaluate ∑k=05k(5k)\displaystyle\sum_{k=0}^{5}k\binom{5}{k}k=0∑5k(k5).Check Show answer Walk through it step by step Practice more like this Review this concept