Counting & ProbabilityEasyBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Easy problemEvaluate ∑k=03(3k)(53−k)\displaystyle\sum_{k=0}^{3}\binom{3}{k}\binom{5}{3-k}k=0∑3(k3)(3−k5).Check Show answer Walk through it step by step Practice more like this Review this concept