Counting & ProbabilityEasyBinomial Theorem, Pascal & Combinatorial Identities ShareBinomial Theorem, Pascal & Combinatorial Identities · Easy problemUse the special case ∑k(nk)2=(2nn)\sum_k\binom{n}{k}^2=\binom{2n}{n}∑k(kn)2=(n2n) to evaluate ∑k=03(3k)2\displaystyle\sum_{k=0}^{3}\binom{3}{k}^2k=0∑3(k3)2.Check Show answer Walk through it step by step Practice more like this Review this concept