Counting & ProbabilityMedium ShareCounting & Probability · Medium problemUsing the identity ∑k=0n(nk)2=(2nn)\displaystyle\sum_{k=0}^{n}\binom{n}{k}^{2}=\binom{2n}{n}k=0∑n(kn)2=(n2n) (a special case of Vandermonde), evaluate ∑k=06(6k)2\displaystyle\sum_{k=0}^{6}\binom{6}{k}^{2}k=0∑6(k6)2.Check Show answer Walk through it step by step Practice more like this