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PutnamSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

Let p(x)=(x−1)(x−2)⋯(x−9)p(x) = (x - 1)(x - 2)\cdots(x - 9). Find p′(9)p\prime(9).