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CalculusSuperchallengeIntegrals I: Feynman's Trick

Integrals I: Feynman's Trick · Superchallenge problem

Apply one step of Newton's method to f(x)=x2−5f(x) = x^2 - 5 starting at x0=2x_0 = 2. Give x1x_1 as a common fraction.