ChallengeSuperchallenge ShareChallenge · Superchallenge problemDefine f(1)=1f(1) = 1f(1)=1 and f(n+1)=f(n)1+2f(n)f(n+1) = \dfrac{f(n)}{1 + 2f(n)}f(n+1)=1+2f(n)f(n). Then f(100)=mnf(100) = \tfrac{m}{n}f(100)=nm in lowest terms. Find m+nm + nm+n.Check Show answer Walk through it step by step Practice more like this