ChallengeSuperchallenge ShareChallenge · Superchallenge problemCompute the exact value of the infinite product (1+12)(1+14)(1+116)(1+1256)⋯\left(1 + \dfrac{1}{2}\right)\left(1 + \dfrac{1}{4}\right)\left(1 + \dfrac{1}{16}\right)\left(1 + \dfrac{1}{256}\right)\cdots(1+21)(1+41)(1+161)(1+2561)⋯, where each factor is 1+2−2k1 + 2^{-2^k}1+2−2k.Check Show answer Walk through it step by step Practice more like this