ChallengeSuperchallengeAdvanced Number Theory ShareAdvanced Number Theory · Superchallenge problemThe product tanπ7tan2π7tan3π7\tan\dfrac{\pi}{7}\tan\dfrac{2\pi}{7}\tan\dfrac{3\pi}{7}tan7πtan72πtan73π equals n\sqrt{n}n for a positive integer nnn. Find nnn.Check Show answer Walk through it step by step Practice more like this Review this concept