ChallengeSuperchallengeAdvanced Number Theory ShareAdvanced Number Theory · Superchallenge problemCompute ∑k=21001k2−1\displaystyle\sum_{k=2}^{100} \frac{1}{k^2 - 1}k=2∑100k2−11. The sum is mn\tfrac{m}{n}nm in lowest terms; find m+nm + nm+n.Check Show answer Walk through it step by step Practice more like this Review this concept