ChallengeSuperchallengeAdvanced Number Theory ShareAdvanced Number Theory · Superchallenge problemThe sequence a1=3a_1 = 3a1=3, a2=18a_2 = 18a2=18 satisfies an=6an−1−9an−2a_n = 6a_{n-1} - 9a_{n-2}an=6an−1−9an−2 for n≥3n \ge 3n≥3. Compute a5a_5a5.Check Show answer Walk through it step by step Practice more like this Review this concept