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ChallengeSuperchallengeAdvanced Number Theory

Advanced Number Theory · Superchallenge problem

The sequence a1=3a_1 = 3, a2=18a_2 = 18 satisfies an=6an−1−9an−2a_n = 6a_{n-1} - 9a_{n-2} for n≥3n \ge 3. Compute a5a_5.