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ChallengeSuperchallengeAdvanced Number Theory

Advanced Number Theory · Superchallenge problem

Compute the product sin⁡π8 sin⁡2π8 sin⁡3π8⋯sin⁡7π8\sin\dfrac{\pi}{8}\,\sin\dfrac{2\pi}{8}\,\sin\dfrac{3\pi}{8}\cdots\sin\dfrac{7\pi}{8}. It equals mn\tfrac{m}{n} for relatively prime positive integers mm and nn. Find m+nm + n.