ChallengeSuperchallengeAdvanced Number Theory ShareAdvanced Number Theory · Superchallenge problemLet L=lcm(8,6)L = \operatorname{lcm}(8, 6)L=lcm(8,6). Find the number of ordered pairs of positive integers (x,y)(x, y)(x,y) with 1x+1y=1L\dfrac{1}{x} + \dfrac{1}{y} = \dfrac{1}{L}x1+y1=L1.Check Show answer Walk through it step by step Practice more like this Review this concept