MathCastle
ChallengeSuperchallengeAdvanced Number Theory

Advanced Number Theory · Superchallenge problem

In triangle ABCABC, point DD lies on ABAB with ADDB=12\tfrac{AD}{DB} = \tfrac12 and point EE lies on ACAC with AEEC=12\tfrac{AE}{EC} = \tfrac12. The ratio [ADE][ABC]=mn\dfrac{[ADE]}{[ABC]} = \tfrac mn in lowest terms. Find m+nm + n.