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ChallengeSuperchallengeAdvanced Number Theory

Advanced Number Theory · Superchallenge problem

A function satisfies f(x)+2f ⁣(1x)=3xf(x) + 2f\!\left(\tfrac1x\right) = 3x for all x≠0x \ne 0. If f ⁣(12)=mnf\!\left(\tfrac12\right) = \tfrac mn in lowest terms, find m+nm + n.