AIMEChallengeAdvanced Number Theory ShareAdvanced Number Theory · Challenge problemLet P=sinπ7 sin2π7 sin3π7P = \sin\dfrac{\pi}{7}\,\sin\dfrac{2\pi}{7}\,\sin\dfrac{3\pi}{7}P=sin7πsin72πsin73π. Then P2=mnP^2 = \tfrac{m}{n}P2=nm, where mmm and nnn are relatively prime positive integers. Find m+nm + nm+n.Check Show answer Walk through it step by step Practice more like this Review this concept