ChallengeSuperchallengeModular Arithmetic ShareModular Arithmetic · Superchallenge problemFind the smallest integer n>1n > 1n>1 such that n2n^2n2 ends in the same three digits as nnn (i.e. n2≡n(mod1000)n^2 \equiv n \pmod{1000}n2≡n(mod1000)).Check Show answer Walk through it step by step Practice more like this Review this concept