GeometryHardCircles & Lines ShareCircles & Lines · Hard problemABCD101416Triangle ABCABCABC has AB=10AB = 10AB=10, AC=14AC = 14AC=14, and BC=16BC = 16BC=16. The bisector of ∠BAC\angle BAC∠BAC meets side BC‾\overline{BC}BC at DDD. What is the area of triangle ABDABDABD?A10310 \sqrt{3}103B20320 \sqrt{3}203C4033\frac{40 \sqrt{3}}{3}3403D5033\frac{50 \sqrt{3}}{3}3503E8033\frac{80 \sqrt{3}}{3}3803Check Show answer Walk through it step by step Practice more like this Review this concept