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GeometryHardAdvanced Number Theory

Advanced Number Theory · Hard problem

ABCMP101214

In △ABC\triangle ABC, AB=10AB = 10, BC=14BC = 14, and CA=12CA = 12. Let MM be the midpoint of BC‾\overline{BC}. The circle passing through AA, BB, and MM meets line ACAC again at a point PP (other than AA). Then AP=pqAP = \dfrac{p}{q} for relatively prime positive integers p,qp, q. Find p+qp+q.