TrigonometryHardAdvanced Number Theory ShareAdvanced Number Theory · Hard problemSuppose tanθ+secθ=3\tan\theta + \sec\theta = 3tanθ+secθ=3 for some real number θ\thetaθ. Then sinθ=mn\sin\theta = \dfrac{m}{n}sinθ=nm for relatively prime positive integers m,nm,nm,n. Find m+nm+nm+n.Check Show answer Walk through it step by step Practice more like this Review this concept