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Differential EquationsHardExact Equations & Substitutions

Exact Equations & Substitutions · Hard problem

The solution of (2xy+3) dx+(x2+4y) dy=0(2xy + 3)\,dx + (x^2 + 4y)\,dy = 0 through (1,1)(1, 1) is x2y+3x+2y2=Cx^2y + 3x + 2y^2 = C. Find CC.