Differential EquationsHardExact Equations & Substitutions ShareExact Equations & Substitutions · Hard problemThe solution of (2xy+3) dx+(x2+4y) dy=0(2xy + 3)\,dx + (x^2 + 4y)\,dy = 0(2xy+3)dx+(x2+4y)dy=0 through (1,1)(1, 1)(1,1) is x2y+3x+2y2=Cx^2y + 3x + 2y^2 = Cx2y+3x+2y2=C. Find CCC.Check Show answer Walk through it step by step Practice more like this Review this concept