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OlympiadSuperchallengeOlympiad Number Theory

Olympiad Number Theory · Superchallenge problem

In triangle ABCABC, AB=5AB = 5, AC=7AC = 7, and BC=8BC = 8. The angle bisector of ∠A\angle A meets BCBC at DD, and the circle through AA, BB, DD meets line ACAC again at EE. Compute CECE.