OlympiadSuperchallengeOlympiad Number Theory ShareOlympiad Number Theory · Superchallenge problemA function f:Q+→Q+f:\mathbb Q^+\to\mathbb Q^+f:Q+→Q+ satisfies f(x) f (yf(x))=f(x+y)f(x)\,f\!\left(y f(x)\right) = f(x + y)f(x)f(yf(x))=f(x+y) for all positive rationals x,yx, yx,y, and f(1)=12f(1) = \dfrac12f(1)=21. Compute f(3)f(3)f(3).Check Show answer Walk through it step by step Practice more like this Review this concept