OlympiadSuperchallengeOlympiad Number Theory ShareOlympiad Number Theory · Superchallenge problemA function f:R→Rf:\mathbb R\to\mathbb Rf:R→R satisfies f(x+y)+f(x−y)=2f(x)f(y)f(x + y) + f(x - y) = 2f(x)f(y)f(x+y)+f(x−y)=2f(x)f(y) for all real x,yx, yx,y, is not identically zero, and f(1)=3f(1) = 3f(1)=3. Compute f(2)f(2)f(2).Check Show answer Walk through it step by step Practice more like this Review this concept